From the magnetic behaviour of (paramagnetic) and (diamagnetic), choose the correct geometry and oxidation state. [2025]

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Q.
From the magnetic behaviour of ${[{NiCl}_{4}]}^{2 -}$ (paramagnetic) and $[Ni {(CO)}_{4}]$ (diamagnetic), choose the correct geometry and oxidation state. [2025]

1 ${[{NiCl}_{4}]}^{2 -} : {Ni}^{II}, tetrahedral$ $[Ni {(CO)}_{4}] : {Ni}^{II}, square planar$

2 ${[{NiCl}_{4}]}^{2 -} : {Ni}^{II}, tetrahedral$ $[Ni {(CO)}_{4}] : Ni (0), tetrahedral$

3 ${[{NiCl}_{4}]}^{2 -} : {Ni}^{II}, square planar$ $[Ni {(CO)}_{4}] : Ni (0), square planar$

4 ${[{NiCl}_{4}]}^{2 -} : Ni (0), tetrahedral$ $[Ni {(CO)}_{4}] : Ni (0), square planar$

Ans.
(2)

In ${[{NiCl}_{4}]}^{2 -},$

Oxidation number of Ni = +2

${}_{28}{Ni} : {}_{18}{[Ar]}$ $3 d^{8} 4 s^{2}$

${Ni}^{2 +} : {}_{18}{[Ar]}$ $3 d^{8}$

In $[Ni {(CO)}_{4}],$

Oxidation number of Ni = 0

${}_{28}{Ni} = {}_{18}{[Ar]}$ $3 d^{8} 4 s^{2}$

CO being a strong field ligand pushes 4s electrons into $3 d^{8}$ orbitals.

Solution

Q.
From the magnetic behaviour of ${[{NiCl}_{4}]}^{2 -}$ (paramagnetic) and $[Ni {(CO)}_{4}]$ (diamagnetic), choose the correct geometry and oxidation state. [2025]

1 ${[{NiCl}_{4}]}^{2 -} : {Ni}^{II}, tetrahedral$ $[Ni {(CO)}_{4}] : {Ni}^{II}, square planar$

2 ${[{NiCl}_{4}]}^{2 -} : {Ni}^{II}, tetrahedral$ $[Ni {(CO)}_{4}] : Ni (0), tetrahedral$

3 ${[{NiCl}_{4}]}^{2 -} : {Ni}^{II}, square planar$ $[Ni {(CO)}_{4}] : Ni (0), square planar$

4 ${[{NiCl}_{4}]}^{2 -} : Ni (0), tetrahedral$ $[Ni {(CO)}_{4}] : Ni (0), square planar$

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Solution

Q. From the magnetic behaviour of [NiCl4]2- (paramagnetic) and [Ni(CO)4] (diamagnetic), choose the correct geometry and oxidation state. [2025]

1 [NiCl4]2-:NiII,tetrahedral [Ni(CO)4]:NiII,square planar

2 [NiCl4]2-:NiII,tetrahedral [Ni(CO)4]:Ni(0),tetrahedral

3 [NiCl4]2-:NiII,square planar [Ni(CO)4]:Ni(0),square planar

4 [NiCl4]2-:Ni(0),tetrahedral [Ni(CO)4]:Ni(0),square planar

Ans. (2) In [NiCl4]2-, Oxidation number of Ni = +2 Ni28:[Ar]183d84s2 Ni2+:[Ar]183d8 In [Ni(CO)4], Oxidation number of Ni = 0 Ni28=[Ar]183d84s2 CO being a strong field ligand pushes 4s electrons into 3d8 orbitals.

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Q.
From the magnetic behaviour of ${[{NiCl}_{4}]}^{2 -}$ (paramagnetic) and $[Ni {(CO)}_{4}]$ (diamagnetic), choose the correct geometry and oxidation state. [2025]

1 ${[{NiCl}_{4}]}^{2 -} : {Ni}^{II}, tetrahedral$ $[Ni {(CO)}_{4}] : {Ni}^{II}, square planar$

2 ${[{NiCl}_{4}]}^{2 -} : {Ni}^{II}, tetrahedral$ $[Ni {(CO)}_{4}] : Ni (0), tetrahedral$

3 ${[{NiCl}_{4}]}^{2 -} : {Ni}^{II}, square planar$ $[Ni {(CO)}_{4}] : Ni (0), square planar$

4 ${[{NiCl}_{4}]}^{2 -} : Ni (0), tetrahedral$ $[Ni {(CO)}_{4}] : Ni (0), square planar$