Fortification of food with iron is done using . The mass in grams of the required to achieve 12 ppm of iron in 150 kg of wheat is _____ (Nearest integer) [Given: Molar mass of Fe, S and O respectively are 56, 32 and 16 g ] [2025]

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Solution

Q.
Fortification of food with iron is done using ${FeSO}_{4} . 7 H_{2} O$ . The mass in grams of the ${FeSO}_{4} . 7 H_{2} O$ required to achieve 12 ppm of iron in 150 kg of wheat is _____ (Nearest integer)

[Given: Molar mass of Fe, S and O respectively are 56, 32 and 16 g ${mol}^{- 1}$ ] [2025]

Ans.
(9)

$ppm = \frac{w_{iron}}{w_{wheat}} \times 10^{6}$

$12 = \frac{w_{iron}}{150} \times 10^{6}$

$w_{iron} = \frac{12 \times 150}{10^{6}} kg = \frac{12 \times 150}{10^{6}} \times 1000 g = 1.8 g$

$Moles of iron = \frac{W_{iron}}{M_{iron}} = \frac{1.8}{56} mol$

${Moles of FeSO}_{4} . 7 H_{2} O = Moles of iron = \frac{1.8}{56} mol$

${Molar mass of FeSO}_{4} . 7 H_{2} O = 56 + 32 + 4 \times 16 + 7 \times 18 = 278 g/mol$

${Mass of FeSO}_{4} . 7 H_{2} O = {moles of FeSO}_{4} . 7 H_{2} O \times {molar mass of FeSO}_{4} . 7 H_{2} O$ $= \frac{1.8}{56} \times 278 g = 8.935 gm \approx 9 gm$

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