For the reaction,2cl(g) Cl2(g) , the correct option is [2020]

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Q.
For the reaction, $2 {Cl}_{(g)} \to {Cl}_{2 (g)}$ , the correct option is [2020]

1 $Δ_{r} H > 0$ and $Δ_{r} S > 0$

2 $Δ_{r} H > 0$ and $Δ_{r} S < 0$

3 $Δ_{r} H < 0$ and $Δ_{r} S > 0$

4 $Δ_{r} H < 0$ and $Δ_{r} S < 0$

Ans.
(4)

In the reaction, $2 {Cl}_{(g)} \to {Cl}_{2 (g)}$ , the randomness decreases as 2 moles of ${Cl}_{(g)}$ are converted to 1 mole of ${Cl}_{2 (g)}$ ; thus, $Δ_{r} S < 0$ .
And this is an exothermic reaction, thus, $Δ_{r} H < 0$ .

Solution

Q.
For the reaction, $2 {Cl}_{(g)} \to {Cl}_{2 (g)}$ , the correct option is [2020]

1 $Δ_{r} H > 0$ and $Δ_{r} S > 0$

2 $Δ_{r} H > 0$ and $Δ_{r} S < 0$

3 $Δ_{r} H < 0$ and $Δ_{r} S > 0$

4 $Δ_{r} H < 0$ and $Δ_{r} S < 0$

Ans.
(4)

In the reaction, $2 {Cl}_{(g)} \to {Cl}_{2 (g)}$ , the randomness decreases as 2 moles of ${Cl}_{(g)}$ are converted to 1 mole of ${Cl}_{2 (g)}$ ; thus, $Δ_{r} S < 0$ .
And this is an exothermic reaction, thus, $Δ_{r} H < 0$ .

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Solution

Q. For the reaction, 2Cl(g)→Cl2(g), the correct option is [2020]

1 ΔrH>0 and ΔrS>0

2 ΔrH>0 and ΔrS<0

3 ΔrH<0 and ΔrS>0

4 ΔrH<0 and ΔrS<0

Ans. (4) In the reaction, 2Cl(g)→Cl2(g), the randomness decreases as 2 moles of Cl(g) are converted to 1 mole of Cl2(g); thus, ΔrS<0. And this is an exothermic reaction, thus, ΔrH<0.

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Q.
For the reaction, $2 {Cl}_{(g)} \to {Cl}_{2 (g)}$ , the correct option is [2020]

1 $Δ_{r} H > 0$ and $Δ_{r} S > 0$

2 $Δ_{r} H > 0$ and $Δ_{r} S < 0$

3 $Δ_{r} H < 0$ and $Δ_{r} S > 0$

4 $Δ_{r} H < 0$ and $Δ_{r} S < 0$

Ans.
(4)

In the reaction, $2 {Cl}_{(g)} \to {Cl}_{2 (g)}$ , the randomness decreases as 2 moles of ${Cl}_{(g)}$ are converted to 1 mole of ${Cl}_{2 (g)}$ ; thus, $Δ_{r} S < 0$ .
And this is an exothermic reaction, thus, $Δ_{r} H < 0$ .