For the given hypothetical reactions, the equilibrium constants are as follows:

Question

$X ⇌ Y; K_{1} = 1.0$

$Y ⇌ Z; K_{2} = 2.0$

$Z ⇌ W; K_{3} = 4.0$

The equilibrium constant for the reaction $X ⇌ W$ is [2024]

Smart Achievers · Accepted Answer

(3)

On adding reactions, equilibrium constants are multiplied

$X ⇌ Y, K_{1} = \frac{[Y]}{[X]}$

$Y ⇌ Z, K_{2} = \frac{[Z]}{[Y]}$

$Z ⇌ W, K_{3} = \frac{[W]}{[Z]}$

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Adding all three:

$X ⇌ W, K = \frac{[W]}{[X]} = \frac{[W] [Z] [Y]}{[Z] [Y] [X]} = K_{1} K_{2} K_{3} = 1 \times 2 \times 4 = 8$

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