For the following reaction at 300 K, The enthalpy change is , then the internal energy change is: [2024]

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Solution

Q.
For the following reaction at 300 K,

$A_{2 (g)} + 3 B_{2 (g)} \to 2 {AB}_{3 (g)}$

The enthalpy change is $+ 15 kJ$ , then the internal energy change is: [2024]

1 19988.4 J

2 200 J

3 1999 J

4 1.9988 kJ

Ans.
(1)

If $n_{p} < n_{r}$ and $Δ n_{g} = n_{p} - n_{r} = - ve$ ; then,

$Δ H < Δ E$

As $Δ H = + 15 kJ$ or $+ 15, 000 J$ , the only possible answer from the given options is 19988.4 J.

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