For the electro chemical cell, Which of the following is correct?

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Q.
For the electro chemical cell

${M|M}^{2 +} ∥ {X|X}^{2 -}$

If $E_{{(M}^{2 +} / M)}^{\circ} = 0.46 V$ and $E_{(X / X^{2 -})}^{\circ} = 0.34 V.$

Which of the following is correct [2024]

1 $E_{cell} = 0.80 V$

2 $M+X \to M^{2 +} + X^{2 -} is a spontaneous reaction$

3 $E_{cell} = - 0.80 V$

4 $M^{2 +} + X^{2 -} \to M+X is a spontaneous reaction$

Ans.
(4)

Anode half cell reaction:

$M \to M^{2 +} + 2 e^{-}, E_{M^{2 +} / M}^{\circ} = 0.46 V$

Cathode half cell reaction:

$X + 2 e^{-} \to X^{2 -}, E_{X / X^{2 -}}^{\circ} = 0.34 V$

Net reaction:

$M + X \to M^{2 +} + X^{2 -},$

$E_{reaction}^{\circ} = E_{X / X^{2 -}}^{\circ} - E_{M^{2 +} / M}^{\circ}$

$= (0.34 - 0.46) V = - 0.12 V$

As potential for the reaction $M + X \to M^{2 +} + X^{2 -}$ is negative, this reaction is non spontaneous.

So its reverse reaction i.e. $M^{2 +} + X^{2 -} \to M + X$ is spontaneous.

Solution

Q.
For the electro chemical cell

${M|M}^{2 +} ∥ {X|X}^{2 -}$

If $E_{{(M}^{2 +} / M)}^{\circ} = 0.46 V$ and $E_{(X / X^{2 -})}^{\circ} = 0.34 V.$

Which of the following is correct [2024]

1 $E_{cell} = 0.80 V$

2 $M+X \to M^{2 +} + X^{2 -} is a spontaneous reaction$

3 $E_{cell} = - 0.80 V$

4 $M^{2 +} + X^{2 -} \to M+X is a spontaneous reaction$

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Solution

Q. For the electro chemical cell M|M2+∥X|X2- If E(M2+/M)∘=0.46 V and E(X/X2-)∘=0.34 V. Which of the following is correct [2024]

1 Ecell=0.80 V

2 M+X→M2++X2- is a spontaneous reaction

3 Ecell=-0.80 V

4 M2++X2-→M+X is a spontaneous reaction

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Q.
For the electro chemical cell

${M|M}^{2 +} ∥ {X|X}^{2 -}$

If $E_{{(M}^{2 +} / M)}^{\circ} = 0.46 V$ and $E_{(X / X^{2 -})}^{\circ} = 0.34 V.$

Which of the following is correct [2024]

1 $E_{cell} = 0.80 V$

2 $M+X \to M^{2 +} + X^{2 -} is a spontaneous reaction$

3 $E_{cell} = - 0.80 V$

4 $M^{2 +} + X^{2 -} \to M+X is a spontaneous reaction$