For a strong electrolyte, a plot of molar conductivity against concentration is a straight line, with a negative slope, the correct unit for the slope is

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Q.
For a strong electrolyte, a plot of molar conductivity against ${(concentration)}^{1 / 2}$ is a straight line, with a negative slope, the correct unit for the slope is [2024]

1 $S$ ${cm}^{2}$ ${mol}^{- 1}$ $L^{1 / 2}$

2 $S$ ${cm}^{2}$ ${mol}^{- 3 / 2}$ $L$

3 $S$ ${cm}^{2}$ ${mol}^{- 3 / 2}$ $L^{- 1 / 2}$

4 $S$ ${cm}^{2}$ ${mol}^{- 3 / 2}$ $L^{1 / 2}$

Ans.
(4)

For strong electrolytes, variation of molar conductivity $(Λ_{m})$ with concentration (C) is given by:

$Λ_{m} = Λ_{m}^{0} - A \sqrt{C}$ , where $Λ_{m}^{0}$ is limiting molar conductivity i.e., molar conductivity at infinite dilution.

From this equation, slope is $-$ A.

Substituting units of all terms:

${Scm}^{2} {mol}^{- 1} = {Scm}^{2} {mol}^{- 1} - (units of A) \sqrt{{mol L}^{- 1}}$

$units of A = \frac{{Scm}^{2} {mol}^{- 1}}{\sqrt{{mol L}^{- 1}}} = {Scm}^{2} {mol}^{- 3 / 2} L^{1 / 2}$

Solution

Q.
For a strong electrolyte, a plot of molar conductivity against ${(concentration)}^{1 / 2}$ is a straight line, with a negative slope, the correct unit for the slope is [2024]

1 $S$ ${cm}^{2}$ ${mol}^{- 1}$ $L^{1 / 2}$

2 $S$ ${cm}^{2}$ ${mol}^{- 3 / 2}$ $L$

3 $S$ ${cm}^{2}$ ${mol}^{- 3 / 2}$ $L^{- 1 / 2}$

4 $S$ ${cm}^{2}$ ${mol}^{- 3 / 2}$ $L^{1 / 2}$

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Solution

Q. For a strong electrolyte, a plot of molar conductivity against (concentration)1/2 is a straight line, with a negative slope, the correct unit for the slope is [2024]

1 S cm2 mol-1 L1/2

2 S cm2 mol-3/2 L

3 S cm2 mol-3/2 L-1/2

4 S cm2 mol-3/2 L1/2

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Q.
For a strong electrolyte, a plot of molar conductivity against ${(concentration)}^{1 / 2}$ is a straight line, with a negative slope, the correct unit for the slope is [2024]

1 $S$ ${cm}^{2}$ ${mol}^{- 1}$ $L^{1 / 2}$

2 $S$ ${cm}^{2}$ ${mol}^{- 3 / 2}$ $L$

3 $S$ ${cm}^{2}$ ${mol}^{- 3 / 2}$ $L^{- 1 / 2}$

4 $S$ ${cm}^{2}$ ${mol}^{- 3 / 2}$ $L^{1 / 2}$