For a reaction, activation energy and the rate constant at 200 K is . The rate constant at 400 K will be [Given that gas constant ] [2019]

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Q.
For a reaction, activation energy $E_{a} = 0$ and the rate constant at 200 K is $1.6 \times 10^{6}$ $s^{- 1}$ . The rate constant at 400 K will be

[Given that gas constant $R = 8.314$ $J$ $K^{- 1}$ ${mol}^{- 1}$ ] [2019]

1 $3.2 \times 10^{4}$ $s^{- 1}$

2 $1.6 \times 10^{6}$ $s^{- 1}$

3 $1.6 \times 10^{3}$ $s^{- 1}$

4 $3.2 \times 10^{6}$ $s^{- 1}$

Ans.
(2)

According to Arrhenius equation,

$\log \frac{k_{2}}{k_{1}} = \frac{E_{a}}{2.303 R} [\frac{T_{2} - T_{1}}{T_{2} T_{1}}]$

$\log \frac{k_{2}}{1.6 \times 10^{6}} = 0; \frac{k_{2}}{1.6 \times 10^{6}} = 1$

$k_{2} = 1.6 \times 10^{6}$ $s^{- 1}$

Solution

Q.
For a reaction, activation energy $E_{a} = 0$ and the rate constant at 200 K is $1.6 \times 10^{6}$ $s^{- 1}$ . The rate constant at 400 K will be

[Given that gas constant $R = 8.314$ $J$ $K^{- 1}$ ${mol}^{- 1}$ ] [2019]

1 $3.2 \times 10^{4}$ $s^{- 1}$

2 $1.6 \times 10^{6}$ $s^{- 1}$

3 $1.6 \times 10^{3}$ $s^{- 1}$

4 $3.2 \times 10^{6}$ $s^{- 1}$

Ans.
(2)

According to Arrhenius equation,

$\log \frac{k_{2}}{k_{1}} = \frac{E_{a}}{2.303 R} [\frac{T_{2} - T_{1}}{T_{2} T_{1}}]$

$\log \frac{k_{2}}{1.6 \times 10^{6}} = 0; \frac{k_{2}}{1.6 \times 10^{6}} = 1$

$k_{2} = 1.6 \times 10^{6}$ $s^{- 1}$

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Solution

Q. For a reaction, activation energy Ea=0 and the rate constant at 200 K is 1.6×106 s-1. The rate constant at 400 K will be [Given that gas constant R=8.314 J K-1 mol-1] [2019]

1 3.2×104 s-1

2 1.6×106 s-1

3 1.6×103 s-1

4 3.2×106 s-1

Ans. (2) According to Arrhenius equation, logk2k1=Ea2.303R[T2-T1T2T1] logk21.6×106=0 ; k21.6×106=1 k2=1.6×106 s-1

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Q.
For a reaction, activation energy $E_{a} = 0$ and the rate constant at 200 K is $1.6 \times 10^{6}$ $s^{- 1}$ . The rate constant at 400 K will be

[Given that gas constant $R = 8.314$ $J$ $K^{- 1}$ ${mol}^{- 1}$ ] [2019]

1 $3.2 \times 10^{4}$ $s^{- 1}$

2 $1.6 \times 10^{6}$ $s^{- 1}$

3 $1.6 \times 10^{3}$ $s^{- 1}$

4 $3.2 \times 10^{6}$ $s^{- 1}$

Ans.
(2)

According to Arrhenius equation,

$\log \frac{k_{2}}{k_{1}} = \frac{E_{a}}{2.303 R} [\frac{T_{2} - T_{1}}{T_{2} T_{1}}]$

$\log \frac{k_{2}}{1.6 \times 10^{6}} = 0; \frac{k_{2}}{1.6 \times 10^{6}} = 1$

$k_{2} = 1.6 \times 10^{6}$ $s^{- 1}$