Q.

For a 3×3 matrix M, let trace (M) denote the sum of all the diagonal elements of M. Let A be a 3×3 matrix such that |A|=12 and trace (A) = 3. If B = adj (adj (2A)), then the value of |B| + trace (B) equals :          [2025]

1 56  
2 280  
3 132  
4 174  

Ans.

(2)

Given, |A|=12, trace (A) = 3

B = adj (adj (2A))           [ adj (adj A)=|A|n2A]

=|2A|32(2A)=23|A|(2A)=8A

 trace(B)=8 trace(A)=8×3=24

Hence, |B| + trace (B)

=83|A|+24=832+24=280.