Following data is for a reaction between reactants A and B, The order of the reaction with respect to A and B, respectively, are: [2024]

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
Following data is for a reaction between reactants A and B:

Rate (mol $L^{- 1}$ $s^{- 1}$ ) [A] [B]

$2 \times 10^{- 3}$ 0.1 M 0.1 M

$4 \times 10^{- 3}$ 0.2 M 0.1 M

$1.6 \times 10^{- 2}$ 0.2 M 0.2 M

The order of the reaction with respect to A and B, respectively, are: [2024]

1 1, 0

2 0, 1

3 1, 2

4 2, 1

Ans.
(3)

Rate = $k {[A]}^{x}$ ${[B]}^{y}$

$2 \times 10^{- 3} = k {[0.1]}^{x}$ ${[0.1]}^{y}$ ...(i)

$4 \times 10^{- 3} = k {[0.2]}^{x}$ ${[0.1]}^{y}$ ...(ii)

$1.6 \times 10^{- 2} = k {[0.2]}^{x}$ ${[0.2]}^{^{y}}$ ...(iii)

Dividing eq. (i) by (ii), we get

$\frac{1}{2} = {(\frac{1}{2})}^{x} \Rightarrow {(\frac{1}{2})}^{1} = {(\frac{1}{2})}^{x} \Rightarrow x = 1$

Similarly, dividing eq. (ii) by (iii), we get

$\frac{1}{4} = {(\frac{1}{2})}^{y} \Rightarrow {(\frac{1}{2})}^{2} = {(\frac{1}{2})}^{y} \Rightarrow y = 2$

Thus, order of the reaction with respect to A and B, respectively are 1 and 2.

Want Us to Email you About Special Offers & Updates?