Enthalpies of formation of CCl4(g), H2O(g), CO2(g) and HCl(g) are -105, -242, -394 and -92 kJ mol-1 respectively. The magnitude of enthalpy of the reaction given below is _________ kJ mol-1. (Nearest Integer)
CCl4(g)+2H2O(g)→CO2(g)+4HCl(g) [2023]
(173)
ΔHf∘=ΔHf∘(CO2,g)+4ΔHf∘(HCl)-ΔHf∘(CCl4)-2ΔHf∘(H2O,r)
=[-394]+4[-92]+105-2×[-242]
=-394-368+105+484
=-173 kJ/mol