Energy released when two deuterons fuse to form a helium nucleus is: (Given: Binding energy per nucleon of and binding energy per nucleon of ) [2025]

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
Energy released when two deuterons $({}_{1}{H^{2}})$ fuse to form a helium nucleus $({}_{2}{He}^{4})$ is:

(Given: Binding energy per nucleon of ${}_{1}{H^{2}} = 1.1 MeV$ and binding energy per nucleon of ${}_{2}{He}^{4} = 7.0 MeV$ ) [2025]

1 8.1 MeV

2 5.9 MeV

3 23.6 MeV

4 26.8 MeV

Ans.
(3)

${}_{1}{H^{2} + {}_{1}{H^{2}} \to {}_{2}{He}^{4}}$

$Q = B E_{Product} - B E_{Reactant}$

$Q = (4 \times 7 - 4 \times 1.1) MeV = 23.6 MeV$

Want Us to Email you About Special Offers & Updates?