Electronic configuration of four elements A, B, C and D are given below : Which of the following is the correct order of increasing electronegativity (Pauling’s scale)? [2025]

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Solution

Q.
Electronic configuration of four elements A, B, C and D are given below : [2025]

(A)   $1 s^{2} 2 s^{2} 2 p^{3}$
(B)   $1 s^{2} 2 s^{2} 2 p^{4}$
(C)   $1 s^{2} 2 s^{2} 2 p^{5}$
(D)   $1 s^{2} 2 s^{2} 2 p^{2}$

Which of the following is the correct order of increasing electronegativity (Pauling’s scale)

1 A < D < B < C

2 A < C < B < D

3 A < B < C < D

4 D < A < B < C

Ans.
(4)

$\to_{Electronegativity increases from left to right in a period.}^{\begin{matrix} (D) & (A) & (B) & (C) \\ 1 s^{2} 2 s^{2} 2 p^{2} & 1 s^{2} 2 s^{2} 2 p^{3} & 1 s^{2} 2 s^{2} 2 p^{4} & 1 s^{2} 2 s^{2} 2 p^{5} \\ Carbon & Nitrogen & Oxygen & Fluorine \end{matrix}}$

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