During the electrolysis of molten sodium chloride, the time required to produce 0.10 mol of chlorine gas using a current of 3 amperes is [2016]

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Solution

Q.
During the electrolysis of molten sodium chloride, the time required to produce 0.10 mol of chlorine gas using a current of 3 amperes is [2016]

1 55 minutes

2 110 minutes

3 220 minutes

4 330 minutes

Ans.
(2)

During the electrolysis of molten sodium chloride,

At cathode : $2 N a^{+} + 2 e^{-} ⟶ 2 N a$

At anode : $2 C l^{-} ⟶ C l_{2} + 2 e^{-}$

$\begin{matrix} _______________________________ \\ Net reaction : 2 N a^{+} + 2 C l^{-} ⟶ 2 N a + C l_{2} \\ _______________________________ \end{matrix}$

According to Faraday’s first law of electrolysis, $W = Z \times I \times t$

$W = \frac{E}{96500} \times I \times t$

No. of moles of $C l_{2}$ gas $\times$ Mol. wt. of $C l_{2}$ gas

$= \frac{Eq. wt. of C l_{2} gas \times I \times t}{96500}$

$0.10 \times 71 = \frac{35.5 \times 3 \times t}{96500}$

$t = \frac{0.10 \times 71 \times 96500}{35.5 \times 3} = 6433.33$ $sec$

$t = \frac{6433.33}{60}$ $min = 107.22$ $min \approx 110$ $min$

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