During estimation of nitrogen by Dumas’ method of compound X (0.42 g): mL of gas will be liberated at STP. (nearest integer) (Given molar mass in g : C : 12, H : 1, N : 14) [2025]

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Solution

Q.
During estimation of nitrogen by Dumas’ method of compound X (0.42 g):

_____ mL of $N_{2}$ gas will be liberated at STP. (nearest integer)

(Given molar mass in g ${mol}^{- 1}$ : C : 12, H : 1, N : 14) [2025]

Ans.
(111)

Molar mass of the compound $(C_{4} N_{2} H_{10})$ $= 4 \times 12 + 2 \times 14 + 10 \times 1 = 86 {g mol}^{- 1}$

$Moles of compound = \frac{Mass of compound}{Molar mass of compound}$ $= \frac{0.42}{86}$ mol

$Moles of N in compound = 2 \times Moles of compound$ $= 2 \times \frac{0.42}{86}$ mol

As all the N of organic compound is converted to $N_{2}$ gas in Duma’s method.

Moles of $N_{2} = \frac{Moles of N}{2}$
$= \frac{0.42}{86} mol$

Volume of $N_{2}$ at STP $= Moles of N_{2} \times 22.7 L = \frac{0.42}{86} \times 22.7 L$

$= 0.11086 L = 110.8 mL \approx 111 mL .$

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