Consider the following reaction approaching equilibrium at 27°C and 1 atm pressure
A+B⇌kr=102kf=103C+D
The standard Gibbs energy change (ΔrGθ) at 27°C is (–) ____kJ mol-1 (Nearest integer).
(Given: R=8.3 J K-1mol-1 and ln10=2.3) [2023]
(6)
Keq=KfKb=103102=10
ΔG°=-RT ln Keq
=-8.3×300 ln (10)
=-8.3×300×2.3
=-5.72×103J mol-1
=-5.72kJ mol-1
≈6 kJ mol-1