Consider the following electrochemical cell at 298 K: If the reaction quotient at a given time is , then the cell EMF is __________ (Nearest integer). Given the standard half-cell reduction potentials as: [2026]

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Solution

Q.
Consider the following electrochemical cell at 298 K:

$Pt | {HSnO}_{2}^{-} (a q) | Sn {(OH)}_{6}^{2 -} (a q) | {OH}^{-} (a q) | {Bi}_{2} O_{3} (s) | Bi (s)$

If the reaction quotient at a given time is $10^{6}$ , then the cell EMF $(E_{cell})$ is __________ $\times 10^{- 1} V$ (Nearest integer).

Given the standard half-cell reduction potentials as:

$E_{{Bi}_{2} O_{3} / Bi, {OH}^{-}}^{\circ} = - 0.44 V$ and $E_{{Sn(OH)}_{6}^{2 -} / {HSnO}_{2}^{-}, {OH}^{-}}^{\circ} = - 0.90 V$ [2026]

Ans.
(4)

$E_{cell}^{\circ} = - 0.44 - (- 0.90)$

$= + 0.46 V$

$Applying Nernst equation:$

$E_{cell} = E_{cell}^{\circ} - \frac{0.06}{n} \log Q$

$E_{cell} = 0.46 - \frac{0.06}{6} \log 10^{6}$

$E_{cell} = 4 \times 10^{- 1}$

$x = 4$

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