Consider the following data:
Heat of combustion of H2(g)=-241.8 kJ mol-1
Heat of combustion of C(g)=-393.5 kJ mol-1
Heat of combustion of C2H5OH(l)=-1234.7 kJ mol-1
The heat of formation of C2H5OH(l) is (-) ________ kJ mol-1 (Nearest Integer) [2023]
(278)
2C(s)+3H2(g)+12O2(g) ⟶ C2H5OH ΔH=?
given
(i) C(s)+O2(g)⟶CO2(g) ΔH1=-393.5 kJ/mol
(ii) H2(g)+12O2(g)⟶H2O(l) ΔH2=-241.8 kJ/mol
(iii) C2H5OH+3O2(g)⟶2CO2(g)+3H2O ΔH=-1234.7 kJ/mol
Required equation =2×eq. (i)+3×eq. (ii)-eq. (iii)
=2(-393.5)+3(-241.8)-(-1234.7)
=-278 kJ/mol