Q.

Consider the following data:

Heat of combustion of H2(g)=-241.8 kJ mol-1

Heat of combustion of C(g)=-393.5 kJ mol-1

Heat of combustion of C2H5OH(l)=-1234.7 kJ mol-1

The heat of formation of C2H5OH(l) is (-) ________ kJ mol-1 (Nearest Integer)                  [2023]


Ans.

(278)

2C(s)+3H2(g)+12O2(g)  C2H5OH    ΔH=?

given

(i)  C(s)+O2(g)CO2(g)    ΔH1=-393.5 kJ/mol

(ii) H2(g)+12O2(g)H2O(l)     ΔH2=-241.8 kJ/mol

(iii) C2H5OH+3O2(g)2CO2(g)+3H2O     ΔH=-1234.7 kJ/mol

Required equation =2×eq. (i)+3×eq. (ii)-eq. (iii)

=2(-393.5)+3(-241.8)-(-1234.7)

=-278 kJ/mol