Q.

Consider a line L passing through the points P(1, 2, 1) and Q(2, 1, –1). If the mirror image of the point A(2, 2, 2) in the line L is (α, β, γ), then α+β+6γ is equal to __________.          [2024]


Ans.

(6)

PQ : x–11=y–2–1=z–1–2=λ (say)

Any point on the line PQ is of the form

B(λ+1,–λ+2,–2λ+1)

 AB→=(λ+1–2)i^+(–λ+2–2)j^+(–2λ+1–2)k^

⇒ AB→=(λ–1)i^–λj^+(–2λ–1)k^  and  PQ→=1i^–j^–2k^

AB→·PQ→=0

⇒ (λ–1)+λ+2(2λ+1)=0

⇒ λ–1+λ+4λ+2=0

⇒ 6λ=–1 ⇒ λ=–16

∴  B(–16+1,16+2,–2(–16)+1)=B(56,136,86)

Now B is mid point of AA'

⇒ (56,136,86)=(α+22,β+22,γ+22)

⇒ α+2=106, β+2=266, γ+2=166

⇒ α=–13, β=73, γ=23

Hence, α+β+6γ=–13+73+6×23=183=6.