Compare the energies of following sets of quantum numbers for multielectron system.

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Q.
Compare the energies of following sets of quantum numbers for multielectron system.

$(A) n = 4, l = 1$

$(B) n = 4, l = 2$

$(C) n = 3, l = 1$

$(D) n = 3, l = 2$

$(E) n = 4, l = 0$

Choose the correct answer from the options given below: [2024]

1 (C) < (E) < (D) < (A) < (B)

2 (E) < (C) < (D) < (A) < (B)

3 (B) > (A) > (C) > (E) > (D)

4 (E) > (C) > (A) > (D) > (B)

Ans.
(1)

For multielectron species, more is value of $n + 1$ for an orbital, more is the energy of the orbital. If two orbitals have same value of $n + 1$ , then the one with higher value of $n$ has higher energy.

Solution

Q.
Compare the energies of following sets of quantum numbers for multielectron system.

$(A) n = 4, l = 1$

$(B) n = 4, l = 2$

$(C) n = 3, l = 1$

$(D) n = 3, l = 2$

$(E) n = 4, l = 0$

Choose the correct answer from the options given below: [2024]

1 (C) < (E) < (D) < (A) < (B)

2 (E) < (C) < (D) < (A) < (B)

3 (B) > (A) > (C) > (E) > (D)

4 (E) > (C) > (A) > (D) > (B)

Ans.
(1)

For multielectron species, more is value of $n + 1$ for an orbital, more is the energy of the orbital. If two orbitals have same value of $n + 1$ , then the one with higher value of $n$ has higher energy.

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Solution

Q. Compare the energies of following sets of quantum numbers for multielectron system. (A) n=4,l=1 (B) n=4,l=2 (C) n=3,l=1 (D) n=3,l=2 (E) n=4,l=0 Choose the correct answer from the options given below: [2024]

1 (C) < (E) < (D) < (A) < (B)

2 (E) < (C) < (D) < (A) < (B)

3 (B) > (A) > (C) > (E) > (D)

4 (E) > (C) > (A) > (D) > (B)

Ans. (1) For multielectron species, more is value of n+1 for an orbital, more is the energy of the orbital. If two orbitals have same value of n+1, then the one with higher value of n has higher energy.

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Q.
Compare the energies of following sets of quantum numbers for multielectron system.

$(A) n = 4, l = 1$

$(B) n = 4, l = 2$

$(C) n = 3, l = 1$

$(D) n = 3, l = 2$

$(E) n = 4, l = 0$

Choose the correct answer from the options given below: [2024]

Ans.
(1)

For multielectron species, more is value of $n + 1$ for an orbital, more is the energy of the orbital. If two orbitals have same value of $n + 1$ , then the one with higher value of $n$ has higher energy.