Cobalt chloride when dissolved in water forms pink coloured complex X which has octahedral geometry. This solution on treating with conc. HCl forms deep blue complex, Y which has a Z geometry. X, Y and Z, respectively, are [2023]

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Q.
Cobalt chloride when dissolved in water forms pink coloured complex X which has octahedral geometry. This solution on treating with conc. HCl forms deep blue complex, Y which has a Z geometry. X, Y and Z, respectively, are [2023]

1 $X = {[Co {(H_{2} O)}_{4} {Cl}_{2}]}^{+}, Y = {[{CoCl}_{4}]}^{2 -}, Z = Tetrahedral$

2 $X = {[Co {(H_{2} O)}_{6}]}^{2 +}, Y = {[{CoCl}_{6}]}^{3 -}, Z = Octahedral$

3 $X = {[Co {(H_{2} O)}_{6}]}^{2 +}, Y = {[{CoCl}_{4}]}^{2 -}, Z = Tetrahedral$

4 $X = {[Co {(H_{2} O)}_{6}]}^{3 +}, Y = {[{CoCl}_{6}]}^{3 -}, Z = Octahedral$

Ans.
(3)

${CoCl}_{2} + H_{2} O ⟶ \underset{\begin{matrix} Pink colour \\ Octahedral \\ ' X' \end{matrix}}{{[Co {(H_{2} O)}_{6}]}^{2 +}} \overset{conc. HCl}{⟶} \underset{\begin{matrix} Deep blue \\ Tetrahedral (Z) \\ ' Y' \end{matrix}}{{[{CoCl}_{4}]}^{2 -}}$

$Hence X = {[Co {(H_{2} O)}_{6}]}^{2 +}, Y = {[{CoCl}_{4}]}^{2 -}, Z = Tetrahedral$

Solution

Q.
Cobalt chloride when dissolved in water forms pink coloured complex X which has octahedral geometry. This solution on treating with conc. HCl forms deep blue complex, Y which has a Z geometry. X, Y and Z, respectively, are [2023]

1 $X = {[Co {(H_{2} O)}_{4} {Cl}_{2}]}^{+}, Y = {[{CoCl}_{4}]}^{2 -}, Z = Tetrahedral$

2 $X = {[Co {(H_{2} O)}_{6}]}^{2 +}, Y = {[{CoCl}_{6}]}^{3 -}, Z = Octahedral$

3 $X = {[Co {(H_{2} O)}_{6}]}^{2 +}, Y = {[{CoCl}_{4}]}^{2 -}, Z = Tetrahedral$

4 $X = {[Co {(H_{2} O)}_{6}]}^{3 +}, Y = {[{CoCl}_{6}]}^{3 -}, Z = Octahedral$

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Solution

Q. Cobalt chloride when dissolved in water forms pink coloured complex X which has octahedral geometry. This solution on treating with conc. HCl forms deep blue complex, Y which has a Z geometry. X, Y and Z, respectively, are [2023]

1 X=[Co(H2O)4Cl2]+,Y=[CoCl4]2-,Z=Tetrahedral

2 X=[Co(H2O)6]2+,Y=[CoCl6]3-,Z=Octahedral

3 X=[Co(H2O)6]2+,Y=[CoCl4]2-,Z=Tetrahedral

4 X=[Co(H2O)6]3+,Y=[CoCl6]3-,Z=Octahedral

Ans. (3) CoCl2+H2O⟶[Co(H2O)6]2+Pink colourOctahedral'X'⟶conc. HCl[CoCl4]2-Deep blueTetrahedral (Z)'Y' Hence X=[Co(H2O)6]2+,Y=[CoCl4]2-,Z=Tetrahedral

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Q.
Cobalt chloride when dissolved in water forms pink coloured complex X which has octahedral geometry. This solution on treating with conc. HCl forms deep blue complex, Y which has a Z geometry. X, Y and Z, respectively, are [2023]

1 $X = {[Co {(H_{2} O)}_{4} {Cl}_{2}]}^{+}, Y = {[{CoCl}_{4}]}^{2 -}, Z = Tetrahedral$

2 $X = {[Co {(H_{2} O)}_{6}]}^{2 +}, Y = {[{CoCl}_{6}]}^{3 -}, Z = Octahedral$

3 $X = {[Co {(H_{2} O)}_{6}]}^{2 +}, Y = {[{CoCl}_{4}]}^{2 -}, Z = Tetrahedral$

4 $X = {[Co {(H_{2} O)}_{6}]}^{3 +}, Y = {[{CoCl}_{6}]}^{3 -}, Z = Octahedral$