Choose the correct option for free expansion of an ideal gas under adiabatic condition from the following:

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Q.
Choose the correct option for free expansion of an ideal gas under adiabatic condition from the following: [2024]

1 $q = 0, Δ T \neq 0, w = 0$

2 $q = 0, Δ T < 0, w \neq 0$

3 $q \neq 0, Δ T = 0, w = 0$

4 $q = 0, Δ T = 0, w = 0$

Ans.
(4)

For adiabatic process $q = 0$ .

   $W = - P_{ext} Δ V, for free expansion, P_{ext} = 0, so w = 0$

  By first law of thermodynamics:

$Δ U = W + q$

$Δ U = 0 + 0 = 0$

  For an ideal gas internal energy is function of temperature, so if $Δ U = 0, Δ T$ is also 0.

Solution

Q.
Choose the correct option for free expansion of an ideal gas under adiabatic condition from the following: [2024]

1 $q = 0, Δ T \neq 0, w = 0$

2 $q = 0, Δ T < 0, w \neq 0$

3 $q \neq 0, Δ T = 0, w = 0$

4 $q = 0, Δ T = 0, w = 0$

Ans.
(4)

For adiabatic process $q = 0$ .

   $W = - P_{ext} Δ V, for free expansion, P_{ext} = 0, so w = 0$

  By first law of thermodynamics:

$Δ U = W + q$

$Δ U = 0 + 0 = 0$

  For an ideal gas internal energy is function of temperature, so if $Δ U = 0, Δ T$ is also 0.

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Solution

Q. Choose the correct option for free expansion of an ideal gas under adiabatic condition from the following: [2024]

1 q=0,ΔT≠0,w=0

2 q=0,ΔT<0,w≠0

3 q≠0,ΔT=0,w=0

4 q=0,ΔT=0,w=0

Ans. (4) For adiabatic process q=0. W=-PextΔV, for free expansion, Pext=0, so w=0 By first law of thermodynamics: ΔU=W+q ΔU=0+0=0 For an ideal gas internal energy is function of temperature, so if ΔU=0,ΔT is also 0.

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Q.
Choose the correct option for free expansion of an ideal gas under adiabatic condition from the following: [2024]

1 $q = 0, Δ T \neq 0, w = 0$

2 $q = 0, Δ T < 0, w \neq 0$

3 $q \neq 0, Δ T = 0, w = 0$

4 $q = 0, Δ T = 0, w = 0$

Ans.
(4)

For adiabatic process $q = 0$ .

$W = - P_{ext} Δ V, for free expansion, P_{ext} = 0, so w = 0$

By first law of thermodynamics:

$Δ U = W + q$

$Δ U = 0 + 0 = 0$

For an ideal gas internal energy is function of temperature, so if $Δ U = 0, Δ T$ is also 0.