Calculate the energy in joule corresponding to light of wavelength 45 nm. (Planck’s constant, J s, speed of light, ) [2014]

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Solution

Q.
Calculate the energy in joule corresponding to light of wavelength 45 nm.
(Planck’s constant, $h = 6.63 \times 10^{- 34}$ J s, speed of light, $c = 3 \times 10^{8} {ms}^{- 1}$ ) [2014]

1 $6.67 \times 10^{15}$

2 $6.67 \times 10^{11}$

3 $4.42 \times 10^{- 15}$

4 $4.42 \times 10^{- 18}$

Ans.
(4)

$E = \frac{h c}{λ} [Given, λ = 45 nm = 45 \times 10^{- 9} m]$

On putting the given values in the equation, we get

$E = \frac{6.63 \times 10^{- 34} \times 3 \times 10^{8}}{45 \times 10^{- 9}} = 4.42 \times 10^{- 18} J$

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