Based on the data given below: The strongest reducing agent is: [2025]

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Solution

Q.
Based on the data given below:

$E_{{Cr}_{2} O_{7}^{2 -} / {Cr}^{3 +}}^{\circ} = 1.33 V E_{{Cl}_{2} / {Cl}^{-}}^{\circ} = 1.36 V$

$E_{{MnO}_{4}^{-} / {Mn}^{2 +}}^{\circ} = 1.51 V E_{{Cr}^{3 +} / Cr}^{\circ} = - 0.74 V$

The strongest reducing agent is: [2025]

1 ${Mn}^{2 +}$

2 ${Cl}^{-}$

3 ${MnO}_{4}^{-}$

4 $Cr$

Ans.
(4)

Strongest reducing agent is the specie which has highest tendency to get oxidized i.e. the one with highest oxidation potential.

Reduction potential Oxidation potential

$E_{{Cr}_{2} O_{7}^{2 -} / {Cr}^{3 +}}^{\circ} = 1.33 V$ $E_{{Cr}^{3 +} / {Cr}_{2} O_{7}^{2 -}}^{\circ} = - 1.33 V$

$E_{{Cl}_{2} / {Cl}^{-}}^{\circ} = 1.36 V$ $E_{{Cl}^{-} / {Cl}_{2}}^{\circ} = - 1.36 V$

$E_{{MnO}_{4}^{-} / {Mn}^{2 +}}^{\circ} = 1.51 V$ $E_{{Mn}^{2 +} / {MnO}_{4}^{-}}^{\circ} = - 1.51 V$

$E_{{Cr}^{3 +} / Cr}^{\circ} = - 0.74 V$ $E_{Cr / {Cr}^{3 +}}^{\circ} = 0.74 V$

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