Assertion (A): The sum of the series with the nth term, an = 9–5n is –465 when number of terms, n = 15.
Reason (R): The sum of first n terms of an AP is given by Sn=n/2[2a+(n-1)d]
(1)
Given nth term an=9-5nFirst term, a1=9-5×1=4⇒a=4Last term, a15=9-5×15=9-75=-66Sum of the series: S15=15/2(a+l)=15/2(4-66)=15/2(- 62)=15×(- 31)=-465Also by the formula,Sn=n/2(2a+(n-1)d)=n/2(a+l)