Assertion (A): If the median and mode of a frequency distribution are 50 and 60, respectively, then its mean is 45.
Reason (R): Mean, median and mode of a frequency distribution are related as:
Mode = 3 (Median) − 2 (Mean)
(1)
Given, median and mode of a frequency distribution are 50 and 60, respectively.
The empirical relationship between mean, mode and median is:
Mode = 3 × Median − 2 × Mean
∴ 60 = 3 × 50 − 2 (Mean)
⇒ Mean = (150 − 60) / 2 = 90 / 2 = 45
Therefore, both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).