As shown in the figure, a block of mass 10 kg lying on a horizontal surface is pulled by a force F acting at an angle of 30° with the horizontal. For , the block will just start to move for the value of F (Given ) [2023]

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Solution

Q.
As shown in the figure, a block of mass 10 kg lying on a horizontal surface is pulled by a force F acting at an angle of 30° with the horizontal. For $μ_{s} = 0.25$ , the block will just start to move for the value of F (Given $g = 10 {m s}^{- 2}$ ) [2023]

1 33.3 N

2 25.2 N

3 20 N

4 35.7 N

Ans.
(2)

$N = M g - F \sin 30 ° = m g - \frac{F}{2} = 100 - \frac{F}{2} = \frac{200 - F}{2}$

$F \cos 30 ° = μ N$

$\sqrt{3} \frac{F}{2} = 0.25 \times (\frac{200 - F}{2})$

$4 \sqrt{3} F = 200 - F$

$F = \frac{200}{4 \sqrt{3} + 1} = 25.22$

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