An organic compound weighing 500 mg, produced 220 mg of on complete combustion. The percentage composition of carbon in the compound is ................. %. (nearest integer) (Given molar mass in g of C : 12, O : 16) [2025]

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Solution

Q.
An organic compound weighing 500 mg, produced 220 mg of ${CO}_{2}$ on complete combustion. The percentage composition of carbon in the compound is ................. %. (nearest integer)

(Given molar mass in g ${mol}^{- 1}$ of C : 12, O : 16) [2025]

Ans.
(12)

${Mass of CO}_{2} produced (W_{C O_{2}}) = 220 mg = 0.22 g$

${Moles of CO}_{2} produced (n_{C O_{2}}) = \frac{W_{C O_{2}}}{M_{C O_{2}}} = \frac{0.22}{44} g = 0.005 mol$

$Moles of carbon in organic compound (n_{C}) = {Moles of CO}_{2} produced (n_{C O_{2}}) = 0.005 mol$

$Mass of carbon in organic compound (W_{C}) = n_{C} \times M_{C}$ $= 0.005 \times 12 g = 0.06 g$

$Percentage of C in organic compound = \frac{W_{C}}{W_{organic compound}} \times 100$ $= \frac{0.06 g}{0.5 g} \times 100 = 12 %$

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