An organic compound contains 78% (by wt) carbon and remaining percentage of hydrogen. The right option for the empirical formula of this compound is [Atomic wt. of C is 12, H is 1] [2021]

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Q.
An organic compound contains 78% (by wt) carbon and remaining percentage of hydrogen. The right option for the empirical formula of this compound is [Atomic wt. of C is 12, H is 1] [2021]

1 ${CH}_{4}$

2 $CH$

3 ${CH}_{2}$

4 ${CH}_{3}$

Ans.
(4)

Given percentage of carbon - 78% and hence percentage of hydrogen - 22%.

Element % Relative number of atoms Simplest ratio

Carbon 78 $\frac{78}{12} = 6.5$ $\frac{6.5}{6.5} = 1$

Hydrogen 22 $\frac{22}{1} = 22$ $\frac{22}{6.5} = 3.3 \approx 3$

$∴$ Empirical formula = ${CH}_{3}$

Solution

Q.
An organic compound contains 78% (by wt) carbon and remaining percentage of hydrogen. The right option for the empirical formula of this compound is [Atomic wt. of C is 12, H is 1] [2021]

1 ${CH}_{4}$

2 $CH$

3 ${CH}_{2}$

4 ${CH}_{3}$

Ans.
(4)

Given percentage of carbon - 78% and hence percentage of hydrogen - 22%.

Element % Relative number of atoms Simplest ratio

Carbon 78 $\frac{78}{12} = 6.5$ $\frac{6.5}{6.5} = 1$

Hydrogen 22 $\frac{22}{1} = 22$ $\frac{22}{6.5} = 3.3 \approx 3$

$∴$ Empirical formula = ${CH}_{3}$

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Element	%	Relative number of atoms	Simplest ratio
Carbon	78	$\frac{78}{12} = 6.5$	$\frac{6.5}{6.5} = 1$
Hydrogen	22	$\frac{22}{1} = 22$	$\frac{22}{6.5} = 3.3 \approx 3$

Solution

Q. An organic compound contains 78% (by wt) carbon and remaining percentage of hydrogen. The right option for the empirical formula of this compound is [Atomic wt. of C is 12, H is 1] [2021]

1 CH4

2 CH

3 CH2

4 CH3

Ans. (4) Given percentage of carbon - 78% and hence percentage of hydrogen - 22%. Element % Relative number of atoms Simplest ratio Carbon 78 7812=6.5 6.56.5=1 Hydrogen 22 221=22 226.5=3.3≈3 ∴ Empirical formula = CH3

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Q.
An organic compound contains 78% (by wt) carbon and remaining percentage of hydrogen. The right option for the empirical formula of this compound is [Atomic wt. of C is 12, H is 1] [2021]

1 ${CH}_{4}$

2 $CH$

3 ${CH}_{2}$

4 ${CH}_{3}$

Ans.
(4)

Given percentage of carbon - 78% and hence percentage of hydrogen - 22%.

Element % Relative number of atoms Simplest ratio

Carbon 78 $\frac{78}{12} = 6.5$ $\frac{6.5}{6.5} = 1$

Hydrogen 22 $\frac{22}{1} = 22$ $\frac{22}{6.5} = 3.3 \approx 3$

$∴$ Empirical formula = ${CH}_{3}$