Q.

An object of mass 0.2 kg executes simple harmonic motion along x axis with frequency of (25π)Hz. At the position x=0.04m the object has kinetic energy 0.5 J and potential energy 0.4 J. The amplitude of oscillation is ________ cm.                [2024]


Ans.

(6)        Total energy =K.E.+P.E.

             x=0.04m,  T.E.=0.5+0.4=0.9J

             12×0.2(2π×25π)2×A2=0.9

             A=0.06m=6cm