Q.

An object moves at a constant speed along a circular path in a horizontal plane with centre at the origin. When the object is at x=+2m, its velocity is -4j^m/s. The object's velocity (v) and acceleration (a) at x=-2m will be              [2023]

1 v=4i^m/s,  a=8j^m/s2  
2 v=4j^m/s,  a=8i^m/s2  
3 v=-4j^m/s,  a=8i^m/s2  
4 v=-4i^m/s,  a=-8j^m/s2  

Ans.

(2)

ac=v2r=422=162=8m/s2

v=4j^ and ac=8i^