An ideal gas has undergone through the cyclic process as shown in the figure. Work done by the gas in the entire cycle is ________ $\times 10^{- 1} J$ . (Take $π$ = 3.14) [2025]

Question

Smart Achievers · Accepted Answer

(314)

Area of circle, $W = π (\frac{△ V}{2}) \cdot (\frac{△ P}{2})$

$W = \frac{π}{4} (500 - 300) \times 10^{3} (350 - 150) \times 10^{- 6}$

$W = 31.4 Joule$

$W = 314 \times 10^{- 1} Joule$

Solution

Q.
An ideal gas has undergone through the cyclic process as shown in the figure. Work done by the gas in the entire cycle is ________ $\times 10^{- 1} J$ . (Take $π$ = 3.14) [2025]

Ans.
(314)

Area of circle, $W = π (\frac{△ V}{2}) \cdot (\frac{△ P}{2})$

$W = \frac{π}{4} (500 - 300) \times 10^{3} (350 - 150) \times 10^{- 6}$

$W = 31.4 Joule$

$W = 314 \times 10^{- 1} Joule$

Want Us to Email you About Special Offers & Updates?

Solution

Q. An ideal gas has undergone through the cyclic process as shown in the figure. Work done by the gas in the entire cycle is ________ ×10–1 J. (Take π = 3.14) [2025]

Ans. (314) Area of circle, W=π(△V2)·(△P2) W=π4(500–300)×103(350–150)×10–6 W=31.4 Joule W=314×10–1 Joule

Want Us to Email you About Special Offers & Updates?

Q.
An ideal gas has undergone through the cyclic process as shown in the figure. Work done by the gas in the entire cycle is ________ $\times 10^{- 1} J$ . (Take $π$ = 3.14) [2025]

Ans.
(314)

Area of circle, $W = π (\frac{△ V}{2}) \cdot (\frac{△ P}{2})$

$W = \frac{π}{4} (500 - 300) \times 10^{3} (350 - 150) \times 10^{- 6}$

$W = 31.4 Joule$

$W = 314 \times 10^{- 1} Joule$