An electric dipole of dipole moment cm is placed in uniform electric field of magnitude V/m. Initially, the dipole moment is parallel to electric field. The work that needs to be done on the dipole to make its dipole moment opposite to the field, will b

Question

An electric dipole of dipole moment $6 \times 10^{- 6}$ cm is placed in uniform electric field of magnitude $10^{6}$ V/m. Initially, the dipole moment is parallel to electric field. The work that needs to be done on the dipole to make its dipole moment opposite to the field, will be ______ J. [2025]

Smart Achievers · Accepted Answer

(12)

Work done in rotating a dipole $= △ U$

or $10^{6}$

$= 2 PE$ ( $∵ θ_{f} = 180 ° and θ_{i} = 0 °$ )

$= (2 \times 6 \times 10^{- 6} \times 10^{6}) J = 12 J$

Solution

Ans.
(12)

Work done in rotating a dipole $= △ U$

or $W = (- PE \cos θ_{f}) - (- PE \cos θ_{i})$

$= 2 PE$ ( $∵ θ_{f} = 180 ° and θ_{i} = 0 °$ )

$= (2 \times 6 \times 10^{- 6} \times 10^{6}) J = 12 J$

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Solution

Q. An electric dipole of dipole moment 6×10–6 cm is placed in uniform electric field of magnitude 106 V/m. Initially, the dipole moment is parallel to electric field. The work that needs to be done on the dipole to make its dipole moment opposite to the field, will be ______ J. [2025]

Ans. (12) Work done in rotating a dipole =△U or W=(–PE cos θf)–(–PE cos θi) =2PE (∵ θf=180° and θi=0°) =(2×6×10–6×106)J=12 J

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Ans.
(12)

Work done in rotating a dipole $= △ U$

or $W = (- PE \cos θ_{f}) - (- PE \cos θ_{i})$

$= 2 PE$ ( $∵ θ_{f} = 180 ° and θ_{i} = 0 °$ )

$= (2 \times 6 \times 10^{- 6} \times 10^{6}) J = 12 J$