Q.

An electric dipole of dipole moment is 6.0×10-6 Cm placed in a uniform electric field of 1.5×103 NC-1 in such a way that the dipole moment is along the electric field. The work done in rotating the dipole by 180° in this field will be _______ mJ.                  [2023]


Ans.

(18)

The work done in rotating the electric dipole=ΔU

             =Uf-Ui

             =(-pEcos180°)-(-pEcos0°)

             =pE+pE=2pE

              =2×6×10-6×1.5×103=18 mJ