An electric bulb rated 50 W – 200 V s connected across a 100 V supply. The power dissipation of the bulb is

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Solution

Q.
An electric bulb rated 50 W – 200 V is connected across a 100 V supply. The power dissipation of the bulb is [2024]

1 12.5 W

2 25 W

3 100 W

4 50 W

Ans.
(1)

Resistance, $R = \frac{V^{2}}{P} = \frac{{(200)}^{2}}{50} = 800 Ω$

Power dissipated, $P = \frac{{(V_{a p p l i e d})}^{2}}{R} = \frac{{(100)}^{2}}{800} = \frac{100}{8} = 12.5 W$

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