Q.

An electric bulb is rated 220 V and 100 W. When it is operated on 110 V, the power consumed will be:

1 100 W  
2 75 W  
3 50 W  
4 25 W  

Ans.

(4)

We know that, P=V2/R

Where,
P = Electric power
V = Potential difference in a circuit
R = Resistance

Now, R=V2P

R=220×220100=484Ω

As the voltage drop across the bulb is 110 V. the power consumed by the bulb is

Pb=V2R     = 110×110484Pb=25 W

Hence the power consumed will be 25 W