An elastic spring under tension of 3 N has a length a. Its length is b under tension 2 N. For its length (3a-2b), the value of tension will be ______ N. [2024]
(5) k(a-x0)=3⇒a=3k+x0 ...(i)
k(b-x0)=2⇒b=2k+x0 ...(ii)
Now, 3a-2b=9k+3x0-4k-2x0=5k+x0
⇒{(3a-2b)-x0}=5k
⇒k{(3a-2b)-x0}=5 ∴T=5N