An aqueous solution of HCl with pH 1.0 is diluted by adding equal volume of water (ignoring dissociation of water). The pH of HCl solution would (Given log 2 = 0.30) [2025]

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Solution

Q.
An aqueous solution of HCl with pH 1.0 is diluted by adding equal volume of water (ignoring dissociation of water). The pH of HCl solution would

(Given log 2 = 0.30) [2025]

1 reduce to 0.5

2 increase to 1.3

3 remain same

4 increase to 2

Ans.
(2)

Initial concentration of $H^{+} ({[H^{+}]}_{initial}) = 10^{- {pH}_{initial}} = 10^{- 1} M$

As equal volume is added, concentration of $H^{+}$ becomes half

$({[H^{+}]}_{initial}) = \frac{10^{- 1}}{2} M$

${pH}_{final} = - \log {[H^{+}]}_{final} = - \log (\frac{10^{- 1}}{2})$

$= - \log (10^{- 1}) + \log 2 = 1 + 0.3 = 1.3$

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