An amount of ice of mass kg and temperature –10°C is transformed to vapour of temperature 110°C by applying heat. The total amount of work required for this conversion is, (Take, specific heat of ice = , specific heat of water = , specific heat of steam = , Latent heat of ice = and Latent heat of steam = ) [2025]
(2)
First, Ice at –10°C Ice at 0°C Water at 0°C. Then, Water at 0°C Water at 100°C Vapour at 100°C Vapour at 110°C