A wire of resistance 20 is divided into 10 equal parts, resulting pairs. A combination of two parts are connected in parallel and so on. Now resulting pairs of parallel combination are connected in series. The equivalent resistance of final combination i

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Solution

Q.
A wire of resistance 20 $Ω$ is divided into 10 equal parts, resulting pairs. A combination of two parts are connected in parallel and so on. Now resulting pairs of parallel combination are connected in series. The equivalent resistance of final combination is ____ $Ω$ . [2024]

Ans.
(5)

Resistance of each part $R = \frac{20}{10} = 2 Ω$

2 parts are connected in parallel $R' = \frac{2}{2} = 1 Ω$

Now, there will be 5 parts, each of resistance $1 Ω$ , they are connected in series.

$R_{eq} = 5 R' \Rightarrow R_{eq} = 5 Ω$

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