A wire of length 25 m and cross-sectional area 5 having resistivity of is bent into a complete circle. The resistance between diametrically opposite points will be [2025]

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Solution

Q.
A wire of length 25 m and cross-sectional area 5 ${mm}^{2}$ having resistivity of $2 \times 10^{- 6} Ωm$ is bent into a complete circle. The resistance between diametrically opposite points will be [2025]

1 12.5 $Ω$

2 50 $Ω$

3 100 $Ω$

4 25 $Ω$

Ans.
(none)

Let R be total resistance across ends of wire, then

$R = \frac{ρ L}{A} = \frac{2 \times 10^{- 6} \times 25}{5 \times 10^{- 6}} = 10 Ω$

$R_{eq} = \frac{R}{4} = \frac{10}{4} = 2.5 Ω$

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