Q.

A wire of length 10 cm and diameter 0.5 mm is used in a bulb. The temperature of the wire is 1727°C and power radiated by the wire is 94.2 W. Its emissivity is x8 where x = ________.

(Given σ=6.0×108 Wm2 K4, π=3.14 and assume that the emissivity of wire material is same at all wavelength.)          [2025]


Ans.

(5)

L = 10 cm, d = 0.5 mm, T = 1727°C = 2000 K

Power, P = 94.2 W

P=εσAT4

94.2=ε×(6×108)(πdL)(2000)4

94.2=ε×(6×108)(3.14)(0.5)(103)(10×102)(2000)4

ε=58  x=5