Q.

A wire of cross-sectional area A, modulus of elasticity 2×1011 Nm-2 and length 2 m is stretched between two vertical rigid supports. When a mass of 2 kg is suspended at the middle, it sags lower from its original position, making an angle θ=1100 radian on the points of support. The value of A is _____ ×10-4 m2 (consider x<<L).          [2024]


Ans.

(1)

tanθ=xLθ,  As θ is small

2Tsinθ=20    Tθ=10

T·1100=10 T=1000 N

Change in length, ΔL=2x2+L2-2L

 ΔL=2L[1+x22L2-1]=x2L

Stress=Ystrain  TA=YΔL(2L)

TA=Y·x2L(2L)=Y2·(x2L2)=Y2·θ2

1000A=Yθ22=2×10112×1100×100

A=1×10-4 m2