A uniform rod of mass 250 g having length 100 cm is balanced on a sharp edge at 40 cm mark. A mass of 400 g is suspended at 10 cm mark. To maintain the balance of the rod, the mass to be suspended at 90 cm mark, is [2025]

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Solution

Q.
A uniform rod of mass 250 g having length 100 cm is balanced on a sharp edge at 40 cm mark. A mass of 400 g is suspended at 10 cm mark. To maintain the balance of the rod, the mass to be suspended at 90 cm mark, is [2025]

1 300 g

2 190 g

3 200 g

4 290 g

Ans.
(2)

$τ_{Net} = 0 \Rightarrow (400 g \times 30) = (250 g \times 10) + (m g \times 50)$

$m = \frac{12000 - 2500}{50} = \frac{9500}{50}$

$m = 190 g$

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