A uniform magnetic field of acts along positive Y-direction. A rectangular loop of sides 20 cm and 10 cm with current of 5A is in Y-Z plane. The current is in anticlockwise sense with reference to negative X axis. Magnitude and direction of the torque is

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Q.
A uniform magnetic field of $2 \times 10^{- 3} T$ acts along positive Y-direction. A rectangular loop of sides 20 cm and 10 cm with current of 5A is in Y-Z plane. The current is in anticlockwise sense with reference to negative X axis. Magnitude and direction of the torque is [2024]

1 $2 \times 10^{- 4} N - m$ along positive Z-direction

2 $2 \times 10^{- 4} N - m$ along negative Z-direction

3 $2 \times 10^{- 4} N - m$ along positive X-direction

4 $2 \times 10^{- 4} N - m$ along positive Y-direction

Ans.
(2)

$\vec{M} = I \vec{A}$

$= 5 \times (0.2) \times (0.1) (- \hat{i}) = 0.1 (- \hat{i})$

$\vec{τ} = \vec{M} \times \vec{B} = 0.1 (- \hat{i}) \times (2 \times 10^{- 3}) (\hat{j})$

$= 2 \times 10^{- 4} (- \hat{k}) N-m$

Solution

Q.
A uniform magnetic field of $2 \times 10^{- 3} T$ acts along positive Y-direction. A rectangular loop of sides 20 cm and 10 cm with current of 5A is in Y-Z plane. The current is in anticlockwise sense with reference to negative X axis. Magnitude and direction of the torque is [2024]

1 $2 \times 10^{- 4} N - m$ along positive Z-direction

2 $2 \times 10^{- 4} N - m$ along negative Z-direction

3 $2 \times 10^{- 4} N - m$ along positive X-direction

4 $2 \times 10^{- 4} N - m$ along positive Y-direction

Ans.
(2)

$\vec{M} = I \vec{A}$

$= 5 \times (0.2) \times (0.1) (- \hat{i}) = 0.1 (- \hat{i})$

$\vec{τ} = \vec{M} \times \vec{B} = 0.1 (- \hat{i}) \times (2 \times 10^{- 3}) (\hat{j})$

$= 2 \times 10^{- 4} (- \hat{k}) N-m$

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Solution

Q. A uniform magnetic field of 2×10-3T acts along positive Y-direction. A rectangular loop of sides 20 cm and 10 cm with current of 5A is in Y-Z plane. The current is in anticlockwise sense with reference to negative X axis. Magnitude and direction of the torque is [2024]

1 2×10-4 N-m along positive Z-direction

2 2×10-4 N-m along negative Z-direction

3 2×10-4 N-m along positive X-direction

4 2×10-4 N-m along positive Y-direction

Ans. (2) M→=IA→ =5×(0.2)×(0.1)(-i^)=0.1(-i^) τ→=M→×B→=0.1(-i^)×(2×10-3)(j^) =2×10-4(-k^) N-m

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Q.
A uniform magnetic field of $2 \times 10^{- 3} T$ acts along positive Y-direction. A rectangular loop of sides 20 cm and 10 cm with current of 5A is in Y-Z plane. The current is in anticlockwise sense with reference to negative X axis. Magnitude and direction of the torque is [2024]

1 $2 \times 10^{- 4} N - m$ along positive Z-direction

2 $2 \times 10^{- 4} N - m$ along negative Z-direction

3 $2 \times 10^{- 4} N - m$ along positive X-direction

4 $2 \times 10^{- 4} N - m$ along positive Y-direction

Ans.
(2)

$\vec{M} = I \vec{A}$

$= 5 \times (0.2) \times (0.1) (- \hat{i}) = 0.1 (- \hat{i})$

$\vec{τ} = \vec{M} \times \vec{B} = 0.1 (- \hat{i}) \times (2 \times 10^{- 3}) (\hat{j})$

$= 2 \times 10^{- 4} (- \hat{k}) N-m$