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Solution


Q.

A uniform magnetic field of 0.4 T acts perpendicular to a circular copper disc 20 cm in radius. The disc is having a uniform angular velocity of 10π rads–1 about an axis through its centre and perpendicular to the disc. What is the potential difference developed between the axis of the disc and the rim (π = 3.14)          [2025]
1 0.0628 V  
2 0.5024 V  
3 0.2512 V  
4 0.1256 V  

Ans.

(3)

Given : B = 0.4 T, r = 20 cm and ω=10π rad/s

The potential difference developed between the axis of the disc and the rim, e=12Bωr2 = 0.2512 V