A transition metal (M) among Mn, Cr, Co and Fe has the highest standard electrode potential . It forms a metal complex of the type . The number of electrons present in the orbital of the complex is ________. [2025]

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Solution

Q.
A transition metal (M) among Mn, Cr, Co and Fe has the highest standard electrode potential $(M^{3 +} / M^{2 +})$ . It forms a metal complex of the type ${[M {(CN)}_{6}]}^{4 -}$ . The number of electrons present in the $e_{g}$ orbital of the complex is ________. [2025]

Ans.
(1)

Among Cr, Mn, Fe and Co, highest $M^{3 +} / M^{2 +}$ potential is of Co.

Cr Mn Fe Co

$M^{3 +} / M^{2 +}$ (in V) –0.41 +1.57 +0.77 +1.97

Thus the complex is ${[Co {(CN)}_{6}]}^{4 -}$ .

Oxidation number of Co = +2, ${Co}^{2 +} = {}_{18}{[Ar]}$ $3 d^{7}$ . As ${CN}^{-}$ is a strong field ligand, $3 d^{7}$ in octahedral field splits as $t_{2 g}^{6} e_{g}^{1}$ . Number of electrons in $e_{g}$ is 1.

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