A train is moving with a speed of 12 m/s on rails which are 1.5 m apart. To negotiate a curve of radius 400 m, the height by which the outer rail should be raised with respect to the inner rail is (Given, g = 10 ):

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Solution

Q.
A train is moving with a speed of 12 m/s on rails which are 1.5 m apart. To negotiate a curve of radius 400 m, the height by which the outer rail should be raised with respect to the inner rail is (Given, g = 10 $m / s^{2}$ ): [2024]

1 6.0 cm

2 5.4 cm

3 4.8 cm

4 4.2 cm

Ans.
(2)

$\tan θ = \frac{v^{2}}{R g} = \frac{12 \times 12}{10 \times 400}$

$\tan θ = \frac{h}{1.5} \Rightarrow \frac{h}{1.5} = \frac{144}{4000}$

$h = 5.4 cm$

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