A thermodynamic system is taken from an original state A to an intermediate state B by a linear process as shown in the figure. Its volume is then reduced to the original value from B to C by an isobaric process. The total work done by the gas from A to B

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Solution

Q.
A thermodynamic system is taken from an original state A to an intermediate state B by a linear process as shown in the figure. Its volume is then reduced to the original value from B to C by an isobaric process. The total work done by the gas from A to B and B to C would be [2024]

1 33800 J

2 2200 J

3 800 J

4 1200 J

Ans.
(3)

Work done $A B = \frac{1}{2} (8000 + 4000) {Dyne/cm}^{2} \times 4 m^{3}$

$= (6000 {Dyne/cm}^{2}) \times 4 m^{3}$

Work done $B C = (4000 {Dyne/cm}^{2}) \times 4 m^{3}$

Total work done $= 2000 {Dyne/cm}^{2} \times 4 m^{3}$

$= 2 \times 10^{3} \times \frac{1}{10^{5}} \frac{N}{{cm}^{2}} \times 4 m^{3}$

$= 2 \times 10^{- 2} \times \frac{N}{10^{- 4} m^{2}} \times 4 m^{3}$

$= 2 \times 10^{2} \times 4 Nm = 800 J$

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