A straight wire AB of mass 40 g and length 50 cm is suspended by a pair of flexible leads in a uniform magnetic field of magnitude 0.40 T as shown in the figure. [2023]

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Solution

Q.
A straight wire AB of mass 40 g and length 50 cm is suspended by a pair of flexible leads in a uniform magnetic field of magnitude 0.40 T as shown in the figure. The magnitude of the current required in the wire to remove the tension in the supporting leads is _________ A. (Take $g = 10 {ms}^{- 2}$ ) [2023]

Ans.
(2)

$For equilibrium M g = I l B$

$I = \frac{m g}{ℓ B} = \frac{40 \times 10^{- 3} \times 10}{50 \times 10^{- 2} \times 0.4} = 2 A$

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